https://ejercicios-fyq.com/ Ejercicios Resueltos, Situaciones de aprendizaje y VÍDEOS de Física y Química para Secundaria y Bachillerato es SPIP - www.spip.net https://ejercicios-fyq.com/local/cache-vignettes/L144xH25/siteon0-da713.png?1758361862 https://ejercicios-fyq.com/ 25 144 https://ejercicios-fyq.com/Kinetic-energy-of-a-moving-projectile-8317 https://ejercicios-fyq.com/Kinetic-energy-of-a-moving-projectile-8317 2024-09-19T04:20:43Z text/html es F_y_Q Kinetic energy SOLVED <p>Calculate the kinetic energy of an 18 g projectile moving horizontally at .</p> - <a href="https://ejercicios-fyq.com/Energy" rel="directory">Energy</a> / <a href="https://ejercicios-fyq.com/Kinetic-energy" rel="tag">Kinetic energy</a>, <a href="https://ejercicios-fyq.com/SOLVED" rel="tag">SOLVED</a> <div class='rss_texte'><p>Calculate the kinetic energy of an 18 g projectile moving horizontally at <img src='https://ejercicios-fyq.com/local/cache-vignettes/L90xH20/0292e51078171553d6decc64fbd4fd45-2cc57.png?1732956060' style='vertical-align:middle;' width='90' height='20' alt="97\ m\cdot s^{-1}" title="97\ m\cdot s^{-1}" />.</math></p></div> <hr /> <div <div class='rss_ps'><p>If you observe the units in the problem statement, you will see that the mass is not expressed in the SI unit of mass. The first thing you need to do is convert it to <i>kg</i> to make the problem homogeneous. <br/> <br/> <img src='https://ejercicios-fyq.com/local/cache-TeX/7d935963158a5faf7edf1f70520d19b8.png' style="vertical-align:middle;" width="219" height="51" alt="18\ \cancel{g}\cdot \frac{1\ kg}{10^3\ \cancel{g}} = \color[RGB]{0,112,192}{\bf 0.018\ kg}" title="18\ \cancel{g}\cdot \frac{1\ kg}{10^3\ \cancel{g}} = \color[RGB]{0,112,192}{\bf 0.018\ kg}" /> <br/> <br/> The kinetic energy of the projectile is given by the equation: <br/> <br/> <img src='https://ejercicios-fyq.com/local/cache-TeX/33d2c0c292dc2a67768a18f873cdc4af.png' style="vertical-align:middle;" width="122" height="43" alt="\color[RGB]{2,112,20}{\bm{E_k= \frac{m}{2}\cdot v^2}}" title="\color[RGB]{2,112,20}{\bm{E_k= \frac{m}{2}\cdot v^2}}" /> <br/> <br/> You know the necessary data, so you just need to substitute and calculate: <br/> <br/> <p class="spip" style="text-align: center;"><img src='https://ejercicios-fyq.com/local/cache-TeX/be5978559ab337f32b73f5bf8b014077.png' style="vertical-align:middle;" width="366" height="44" alt="E_k = \frac{0.018\ kg}{2}\cdot 97^2\ m^2\cdot s^{-2} = \fbox{\color[RGB]{192,0,0}{\bf 84.7\ J}}" title="E_k = \frac{0.018\ kg}{2}\cdot 97^2\ m^2\cdot s^{-2} = \fbox{\color[RGB]{192,0,0}{\bf 84.7\ J}}" /></p> </math></p></div> https://ejercicios-fyq.com/Kinetic-energy-of-an-object-3440 https://ejercicios-fyq.com/Kinetic-energy-of-an-object-3440 2016-01-02T04:58:14Z text/html es F_y_Q Kinetic energy SOLVED <p>An object with a mass of 2 kg is falling at a speed of . What is the kinetic energy of this object?</p> - <a href="https://ejercicios-fyq.com/Energy" rel="directory">Energy</a> / <a href="https://ejercicios-fyq.com/Kinetic-energy" rel="tag">Kinetic energy</a>, <a href="https://ejercicios-fyq.com/SOLVED" rel="tag">SOLVED</a> <div class='rss_texte'><p>An object with a mass of 2 kg is falling at a speed of <img src='https://ejercicios-fyq.com/local/cache-vignettes/L79xH20/548e48915e69b2a45652a192de14ac6e-aefb5.png?1733121826' style='vertical-align:middle;' width='79' height='20' alt="7\ m\cdot s^{-1}" title="7\ m\cdot s^{-1}" />. What is the kinetic energy of this object?</math></p></div> <hr /> <div <div class='rss_ps'><p>The equation for kinetic energy is: <br/> <p class="spip" style="text-align: center;"><img src='https://ejercicios-fyq.com/local/cache-TeX/6595944ccfbf1b4cf18f63abe46e69db.png' style="vertical-align:middle;" width="525" height="46" alt="{\color[RGB]{2,112,20}{\bm{E_k = \frac{1}{2}\cdot m\cdot v^2}}}\ \to\ E_k = \frac{1}{2}\cdot 2\ kg\cdot 7^2\ m^2\cdot s^{-2} = \fbox{\color[RGB]{192,0,0}{\bf 49\ J}}" title="{\color[RGB]{2,112,20}{\bm{E_k = \frac{1}{2}\cdot m\cdot v^2}}}\ \to\ E_k = \frac{1}{2}\cdot 2\ kg\cdot 7^2\ m^2\cdot s^{-2} = \fbox{\color[RGB]{192,0,0}{\bf 49\ J}}" /></p> </math></p></div>