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	<title>EjerciciosFyQ</title>
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	<description>Ejercicios Resueltos, Situaciones de aprendizaje y V&#205;DEOS de F&#237;sica y Qu&#237;mica para Secundaria y Bachillerato</description>
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		<title>Frequency and energy of light (4330)</title>
		<link>https://ejercicios-fyq.com/Frequency-and-energy-of-light-4330</link>
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		<dc:date>2017-12-05T06:11:55Z</dc:date>
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		<dc:creator>F_y_Q</dc:creator>


		<dc:subject>Frequency</dc:subject>
		<dc:subject>Energy</dc:subject>
		<dc:subject>SOLVED</dc:subject>

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&lt;p&gt;If frequency of red light is lower than frequency of blue light, how will their energies compare?&lt;/p&gt;


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&lt;a href="https://ejercicios-fyq.com/Waves" rel="directory"&gt;Waves&lt;/a&gt;

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&lt;a href="https://ejercicios-fyq.com/Frequency" rel="tag"&gt;Frequency&lt;/a&gt;, 
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 <content:encoded>&lt;div class='rss_texte'&gt;&lt;p&gt;If frequency of red light is lower than frequency of blue light, how will their energies compare?&lt;/p&gt;&lt;/div&gt;
		&lt;hr /&gt;
		&lt;div &lt;div class='rss_ps'&gt;&lt;p&gt;The energy of blue light will be higher than the energy of red light. You must remember Planck's equation, which gives us the relationship between these two magnitudes: &lt;br/&gt; &lt;br/&gt; &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/715dd37cc8b71bff8a0e3d0e0bfddb1d.png' style=&#034;vertical-align:middle;&#034; width=&#034;92&#034; height=&#034;16&#034; alt=&#034;\color[RGB]{2,112,20}{\bm{E= h\cdot \nu}}&#034; title=&#034;\color[RGB]{2,112,20}{\bm{E= h\cdot \nu}}&#034; /&gt; &lt;br/&gt; &lt;br/&gt; &lt;b&gt;This equation establishes that the higher the frequency, the higher the energy&lt;/b&gt;.&lt;/math&gt;&lt;/p&gt;&lt;/div&gt;
		
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		<title>Sound's tone (3622)</title>
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		<dc:date>2016-06-30T05:38:35Z</dc:date>
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		<dc:creator>F_y_Q</dc:creator>


		<dc:subject>Frequency</dc:subject>
		<dc:subject>SOLVED</dc:subject>

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&lt;p&gt;What is the physical magnitude of sound related to tone?&lt;/p&gt;


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&lt;a href="https://ejercicios-fyq.com/Waves" rel="directory"&gt;Waves&lt;/a&gt;

/ 
&lt;a href="https://ejercicios-fyq.com/Frequency" rel="tag"&gt;Frequency&lt;/a&gt;, 
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 <content:encoded>&lt;div class='rss_texte'&gt;&lt;p&gt;What is the physical magnitude of sound related to tone?&lt;/p&gt;&lt;/div&gt;
		&lt;hr /&gt;
		&lt;div &lt;div class='rss_ps'&gt;&lt;p&gt;Tone is related to the &lt;b&gt;frequency&lt;/b&gt; of the sound wave.&lt;/p&gt;&lt;/div&gt;
		
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		<title>Relation between frequency and wavelength (3140)</title>
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		<dc:date>2015-05-08T09:14:21Z</dc:date>
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		<dc:language>es</dc:language>
		<dc:creator>F_y_Q</dc:creator>


		<dc:subject>Propagation speed</dc:subject>
		<dc:subject>Frequency</dc:subject>
		<dc:subject>Wavelength</dc:subject>
		<dc:subject>SOLVED</dc:subject>

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&lt;p&gt;A spring is producing waves with a frequency of 4 Hz and a wavelength 0.5 m. What is its velocity? What will be its wavelength if the frequency is doubled? What will be its wavelength if the frequency is reduced to half?&lt;/p&gt;


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&lt;a href="https://ejercicios-fyq.com/Waves" rel="directory"&gt;Waves&lt;/a&gt;

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 <content:encoded>&lt;div class='rss_texte'&gt;&lt;p&gt;A spring is producing waves with a frequency of 4 Hz and a wavelength 0.5 m. What is its velocity? What will be its wavelength if the frequency is doubled? What will be its wavelength if the frequency is reduced to half?&lt;/p&gt;&lt;/div&gt;
		&lt;hr /&gt;
		&lt;div &lt;div class='rss_ps'&gt;&lt;p&gt;The wave's velocity is: &lt;br/&gt; &lt;br/&gt; &lt;p class=&#034;spip&#034; style=&#034;text-align: center;&#034;&gt;&lt;img src='https://ejercicios-fyq.com/local/cache-TeX/01c027dfa14d6b8ca71d2cd5e077c506.png' style=&#034;vertical-align:middle;&#034; width=&#034;372&#034; height=&#034;37&#034; alt=&#034;{\color[RGB]{2,112,20}{\bm{v = \lambda \cdot \nu}}}\ \to\ v = 0.5\ m\cdot 4\ s^{-1} = \fbox{\color[RGB]{192,0,0}{\bm{2\ \frac{m}{s}}}}&#034; title=&#034;{\color[RGB]{2,112,20}{\bm{v = \lambda \cdot \nu}}}\ \to\ v = 0.5\ m\cdot 4\ s^{-1} = \fbox{\color[RGB]{192,0,0}{\bm{2\ \frac{m}{s}}}}&#034; /&gt;&lt;/p&gt; &lt;br/&gt; If velocity is constant, when the frequency is doubled, &lt;b&gt;the wavelength must be halved&lt;/b&gt;. &lt;br/&gt; &lt;br/&gt; Similarly, if the frequency is halved, &lt;b&gt;the wavelength must be doubled&lt;/b&gt;.&lt;/math&gt;&lt;/p&gt;&lt;/div&gt;
		
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