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		<title>Calorimetry: final temperature of a mixture (8297)</title>
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		<dc:date>2024-09-02T03:37:09Z</dc:date>
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		<dc:language>es</dc:language>
		<dc:creator>F_y_Q</dc:creator>


		<dc:subject>Calorimetry</dc:subject>
		<dc:subject>Temperature</dc:subject>
		<dc:subject>SOLVED</dc:subject>

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&lt;p&gt;100 g of water at is mixed with 300 g of water at . What will be the final temperature of the mixture?&lt;/p&gt;


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 <content:encoded>&lt;div class='rss_texte'&gt;&lt;p&gt;100 g of water at &lt;img src='https://ejercicios-fyq.com/local/cache-vignettes/L50xH17/513d73beaa9ae362e57006fb5c16c382-3f234.png?1733002651' style='vertical-align:middle;' width='50' height='17' alt=&#034;10\ ^oC&#034; title=&#034;10\ ^oC&#034; /&gt; is mixed with 300 g of water at &lt;img src='https://ejercicios-fyq.com/local/cache-vignettes/L55xH42/df740a9202d22e3b71445ce1efcd70b9-39cd9.png?1732977318' style='vertical-align:middle;' width='55' height='42' alt=&#034;40\ ^oC&#034; title=&#034;40\ ^oC&#034; /&gt;. What will be the final temperature of the mixture?&lt;/math&gt;&lt;/p&gt;&lt;/div&gt;
		&lt;hr /&gt;
		&lt;div &lt;div class='rss_ps'&gt;&lt;p&gt;The heat lost by the hot water is equal to the heat gained by the cold water.&lt;br/&gt; &lt;br/&gt; For the hot water: &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/7677908c73c18f810c657a3f3848082a.png' style=&#034;vertical-align:middle;&#034; width=&#034;337&#034; height=&#034;23&#034; alt=&#034;\color[RGB]{2,112,20}{\bm{Q_{hot} =m_{hot}\cdot c_e(H_2O)\cdot (T_f - T_i)}}&#034; title=&#034;\color[RGB]{2,112,20}{\bm{Q_{hot} =m_{hot}\cdot c_e(H_2O)\cdot (T_f - T_i)}}&#034; /&gt; &lt;br/&gt; &lt;br/&gt; For the cold water: &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/911e7b6c22a10519790749321e41f11e.png' style=&#034;vertical-align:middle;&#034; width=&#034;349&#034; height=&#034;23&#034; alt=&#034;\color[RGB]{2,112,20}{\bm{Q_{cold} =m_{cold}\cdot c_e(H_2O)\cdot (T_f - T_i)}}&#034; title=&#034;\color[RGB]{2,112,20}{\bm{Q_{cold} =m_{cold}\cdot c_e(H_2O)\cdot (T_f - T_i)}}&#034; /&gt; &lt;br/&gt; &lt;br/&gt; The heat lost is considered negative, and the heat gained is positive: &lt;br/&gt; &lt;br/&gt; &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/473d251aa211eaf398290e1af004d3f5.png' style=&#034;vertical-align:middle;&#034; width=&#034;144&#034; height=&#034;21&#034; alt=&#034;\color[RGB]{2,112,20}{\bm{Q_{cold}= - Q_{hot}}}&#034; title=&#034;\color[RGB]{2,112,20}{\bm{Q_{cold}= - Q_{hot}}}&#034; /&gt; &lt;br/&gt; &lt;br/&gt; Equating the heat exchanges: &lt;br/&gt; &lt;br/&gt; &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/54be27a30b1898d68fd5755ec36078b6.png' style=&#034;vertical-align:middle;&#034; width=&#034;588&#034; height=&#034;23&#034; alt=&#034;100\ g\cdot c_e(\ce{H2O})\cdot (T_f - 10\ ^oC) = - 300\ g\cdot c_e(\ce{H2O})\cdot (T_f - 40\ ^oC)&#034; title=&#034;100\ g\cdot c_e(\ce{H2O})\cdot (T_f - 10\ ^oC) = - 300\ g\cdot c_e(\ce{H2O})\cdot (T_f - 40\ ^oC)&#034; /&gt; &lt;br/&gt; &lt;br/&gt; Eliminating the specific heat of water from the equation and simplifying: &lt;br/&gt; &lt;br/&gt; &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/caa7375d89ade215b0e3db49af3831be.png' style=&#034;vertical-align:middle;&#034; width=&#034;275&#034; height=&#034;23&#034; alt=&#034;-T_f + 10\ ^oC = 3\ T_f - 120\ ^oC&#034; title=&#034;-T_f + 10\ ^oC = 3\ T_f - 120\ ^oC&#034; /&gt; &lt;br/&gt; &lt;br/&gt; Solving for the final temperature: &lt;br/&gt; &lt;br/&gt; &lt;p class=&#034;spip&#034; style=&#034;text-align: center;&#034;&gt;&lt;img src='https://ejercicios-fyq.com/local/cache-TeX/2b227ae2c39d10cec30a6a5602010763.png' style=&#034;vertical-align:middle;&#034; width=&#034;325&#034; height=&#034;34&#034; alt=&#034;130\ ^oC = 4\ T_f\ \to\ \fbox{\color[RGB]{192,0,0}{\bm{32.5\ ^oC = T_f}}}&#034; title=&#034;130\ ^oC = 4\ T_f\ \to\ \fbox{\color[RGB]{192,0,0}{\bm{32.5\ ^oC = T_f}}}&#034; /&gt;&lt;/p&gt;
&lt;/math&gt;&lt;/p&gt;&lt;/div&gt;
		
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