https://ejercicios-fyq.com/ Ejercicios Resueltos, Situaciones de aprendizaje y VÍDEOS de Física y Química para Secundaria y Bachillerato es SPIP - www.spip.net https://ejercicios-fyq.com/local/cache-vignettes/L144xH25/siteon0-da713.png?1758361862 https://ejercicios-fyq.com/ 25 144 https://ejercicios-fyq.com/Efficiency-and-useful-power-8300 https://ejercicios-fyq.com/Efficiency-and-useful-power-8300 2024-09-07T03:10:02Z text/html es F_y_Q Power Efficiency SOLVED <p>A motor is supplied with a power of 1 000 W. If the efficiency of this motor is , calculate the useful power and the lost power.</p> - <a href="https://ejercicios-fyq.com/Energy" rel="directory">Energy</a> / <a href="https://ejercicios-fyq.com/Power" rel="tag">Power</a>, <a href="https://ejercicios-fyq.com/Efficiency" rel="tag">Efficiency</a>, <a href="https://ejercicios-fyq.com/SOLVED" rel="tag">SOLVED</a> <div class='rss_texte'><p>A motor is supplied with a power of 1 000 W. If the efficiency of this motor is <img src='https://ejercicios-fyq.com/local/cache-vignettes/L32xH14/e3de74591a3bb01cc6057dd4cfc8eff5-34645.png?1732958364' style='vertical-align:middle;' width='32' height='14' alt="80\ \%" title="80\ \%" />, calculate the useful power and the lost power.</math></p></div> <hr /> <div <div class='rss_ps'><p>Efficiency or performance is the ratio between the useful power and the supplied power: <br/> <br/> <img src='https://ejercicios-fyq.com/local/cache-TeX/916d754a2a89d8305f376635540b523b.png' style="vertical-align:middle;" width="130" height="51" alt="\color[RGB]{2,112,20}{\bm{\rho = \frac{P_u}{P_T}\cdot 100}}" title="\color[RGB]{2,112,20}{\bm{\rho = \frac{P_u}{P_T}\cdot 100}}" /> <br/> <br/> The useful power will be: <br/> <br/> <p class="spip" style="text-align: center;"><img src='https://ejercicios-fyq.com/local/cache-TeX/bf41b7fbd9e3f8f16ea4a6e5c71bf7cf.png' style="vertical-align:middle;" width="389" height="45" alt="P_u = \frac{80}{100}\cdot P_T = 0.8\cdot 1\ 000\ W = \fbox{\color[RGB]{192,0,0}{\bf 800\ W}}" title="P_u = \frac{80}{100}\cdot P_T = 0.8\cdot 1\ 000\ W = \fbox{\color[RGB]{192,0,0}{\bf 800\ W}}" /></p> <br/> The lost power will be the difference between the supplied and the used power: <br/> <br/> <p class="spip" style="text-align: center;"><img src='https://ejercicios-fyq.com/local/cache-TeX/fe923c3b43cea3c5a7cf254d822c035f.png' style="vertical-align:middle;" width="262" height="28" alt="(1\ 000 - 800)\ W = \fbox{\color[RGB]{192,0,0}{\bf 200\ W}}" title="(1\ 000 - 800)\ W = \fbox{\color[RGB]{192,0,0}{\bf 200\ W}}" /></p> </math></p></div>