https://ejercicios-fyq.com/ Ejercicios Resueltos, Situaciones de aprendizaje y VÍDEOS de Física y Química para Secundaria y Bachillerato es SPIP - www.spip.net https://ejercicios-fyq.com/local/cache-vignettes/L144xH25/siteon0-da713.png?1758361862 https://ejercicios-fyq.com/ 25 144 https://ejercicios-fyq.com/Acceleration-of-an-elevator-with-different-readings-on-the-weighing-scale-7068 https://ejercicios-fyq.com/Acceleration-of-an-elevator-with-different-readings-on-the-weighing-scale-7068 2021-03-12T05:53:59Z text/html es F_y_Q Acceleration Non-inertial system Dynamics SOLVED <p>A person with a mass of 70 kg stands on a weighing scale in a moving elevator and observes different readings. Determine the acceleration of the elevator and wether it is moving up, down, accelereting, decelerating or stationary if the scale readings are: a) 66 kg, b) 74 kg and c) 70 kg.</p> - <a href="https://ejercicios-fyq.com/Dynamics" rel="directory">Dynamics</a> / <a href="https://ejercicios-fyq.com/Acceleration" rel="tag">Acceleration</a>, <a href="https://ejercicios-fyq.com/Non-inertial-system" rel="tag">Non-inertial system</a>, <a href="https://ejercicios-fyq.com/Dynamics-663" rel="tag">Dynamics</a>, <a href="https://ejercicios-fyq.com/SOLVED" rel="tag">SOLVED</a> <div class='rss_texte'><p>A person with a mass of 70 kg stands on a weighing scale in a moving elevator and observes different readings. Determine the acceleration of the elevator and wether it is moving up, down, accelereting, decelerating or stationary if the scale readings are: a) 66 kg, b) 74 kg and c) 70 kg.</p></div> <hr /> <div <div class='rss_ps'><p>Weight and normal force have opposite sense and the following equation is used: <br/> <br/> <img src='https://ejercicios-fyq.com/local/cache-TeX/824578b0ae81d170cf8c60d8ac58d1fb.png' style="vertical-align:middle;" width="356" height="50" alt="p - N = m\cdot a\ \to\ \color[RGB]{2,112,20}{\bm{a= \frac{(m - m^{\prime})\cdot g}{m}}}" title="p - N = m\cdot a\ \to\ \color[RGB]{2,112,20}{\bm{a= \frac{(m - m^{\prime})\cdot g}{m}}}" /> <br/> <br/> Just substitute the values and calculate the acceleration in each case: <br/> <br/> a) <p class="spip" style="text-align: center;"><img src='https://ejercicios-fyq.com/local/cache-TeX/eb9528a74984c5a0767e8db66ccdec15.png' style="vertical-align:middle;" width="339" height="60" alt="a = \frac{(70 - 66)\ \cancel{kg}\cdot 9.8\ \frac{m}{s^2}}{70\ \cancel{kg}}= \fbox{\color[RGB]{192,0,0}{\bm{0.56\ \frac{m}{s^2}}}}" title="a = \frac{(70 - 66)\ \cancel{kg}\cdot 9.8\ \frac{m}{s^2}}{70\ \cancel{kg}}= \fbox{\color[RGB]{192,0,0}{\bm{0.56\ \frac{m}{s^2}}}}" /></p> <br/> <b>The elevator is moving down</b>. <br/> <br/> b) <p class="spip" style="text-align: center;"><img src='https://ejercicios-fyq.com/local/cache-TeX/4c6006e382a7c44ee3f18b2ae5aaaf60.png' style="vertical-align:middle;" width="359" height="60" alt="a = \frac{(70 - 74)\ \cancel{kg}\cdot 9.8\ \frac{m}{s^2}}{70\ \cancel{kg}}= \fbox{\color[RGB]{192,0,0}{\bm{- 0.56\ \frac{m}{s^2}}}}" title="a = \frac{(70 - 74)\ \cancel{kg}\cdot 9.8\ \frac{m}{s^2}}{70\ \cancel{kg}}= \fbox{\color[RGB]{192,0,0}{\bm{- 0.56\ \frac{m}{s^2}}}}" /></p> <br/> <b>The elevator is moving up</b>. <br/> <br/> c) <p class="spip" style="text-align: center;"><img src='https://ejercicios-fyq.com/local/cache-TeX/1ec9cfef4e5b95ceeb98f835d2c9f51d.png' style="vertical-align:middle;" width="309" height="60" alt="a = \frac{(70 - 70)\ \cancel{kg}\cdot 9.8\ \frac{m}{s^2}}{70\ \cancel{kg}}= \fbox{\color[RGB]{192,0,0}{\bm{0\ \frac{m}{s^2}}}}" title="a = \frac{(70 - 70)\ \cancel{kg}\cdot 9.8\ \frac{m}{s^2}}{70\ \cancel{kg}}= \fbox{\color[RGB]{192,0,0}{\bm{0\ \frac{m}{s^2}}}}" /></p> <br/> <b>The elevator is not moving</b>.</math></p></div>