https://ejercicios-fyq.com/ Ejercicios Resueltos, Situaciones de aprendizaje y VÍDEOS de Física y Química para Secundaria y Bachillerato es SPIP - www.spip.net https://ejercicios-fyq.com/local/cache-vignettes/L144xH25/siteon0-da713.png?1758361862 https://ejercicios-fyq.com/ 25 144 https://ejercicios-fyq.com/Solutions-Percentage-by-mass-1931 https://ejercicios-fyq.com/Solutions-Percentage-by-mass-1931 2012-11-10T07:55:39Z text/html es F_y_Q Solutions Percentage by mass SOLVED <p>Make a solution by mixing 22 g of sugar and 240 mL of milk. Determine the percentage by mass of this solution. How much sugar is needed to prepare 500 g of solution with the same concentration? <br class='autobr' /> Average density of milk is .</p> - <a href="https://ejercicios-fyq.com/Solutions-271" rel="directory">Solutions</a> / <a href="https://ejercicios-fyq.com/Solutions-660" rel="tag">Solutions</a>, <a href="https://ejercicios-fyq.com/Percentage-by-mass" rel="tag">Percentage by mass</a>, <a href="https://ejercicios-fyq.com/SOLVED" rel="tag">SOLVED</a> <div class='rss_texte'><p>Make a solution by mixing 22 g of sugar and 240 mL of milk. Determine the percentage by mass of this solution. How much sugar is needed to prepare 500 g of solution with the same concentration?</p> <p>Average density of milk is <img src='https://ejercicios-fyq.com/local/cache-vignettes/L121xH24/2206c99476a92d0e3dd8df6c47e6f879-3757a.png?1732956019' style='vertical-align:middle;' width='121' height='24' alt="1.03\ g\cdot mL^{-1}" title="1.03\ g\cdot mL^{-1}" />.</math></p></div> <hr /> <div <div class='rss_ps'><p>The mass of milk used for the mixture is: <br/> <br/> <img src='https://ejercicios-fyq.com/local/cache-TeX/1c73770d1fdf774e1bbc902ec655d4ad.png' style="vertical-align:middle;" width="248" height="47" alt="240\ \cancel{mL}\cdot \frac{1.03\ g}{1\ \cancel{mL}} = \color[RGB]{0,112,192}{\bf 247.2\ g}" title="240\ \cancel{mL}\cdot \frac{1.03\ g}{1\ \cancel{mL}} = \color[RGB]{0,112,192}{\bf 247.2\ g}" /> <br/> <br/> The total mass of the solution is: <br/> <br/> <img src='https://ejercicios-fyq.com/local/cache-TeX/fd21c5fc2aaa88031f7651d4930c3e9f.png' style="vertical-align:middle;" width="482" height="23" alt="m_T = m_S + m_d = (22 + 247.2)\ g\ \to\ m_D = \color[RGB]{0,112,192}{\bf 269.2\ g}" title="m_T = m_S + m_d = (22 + 247.2)\ g\ \to\ m_D = \color[RGB]{0,112,192}{\bf 269.2\ g}" /> <br/> <br/> The mass percentage is: <br/> <br/> <p class="spip" style="text-align: center;"><img src='https://ejercicios-fyq.com/local/cache-TeX/38cb9992a9391a5d6a27803de6e81f53.png' style="vertical-align:middle;" width="416" height="51" alt="\%(m) = \frac{m_S}{m_T}\cdot 100 = \frac{22\ \cancel{g}}{269.2\ \cancel{g}}\cdot 100 = \fbox{\color[RGB]{192,0,0}{\bf 8.17\ \%}}" title="\%(m) = \frac{m_S}{m_T}\cdot 100 = \frac{22\ \cancel{g}}{269.2\ \cancel{g}}\cdot 100 = \fbox{\color[RGB]{192,0,0}{\bf 8.17\ \%}}" /></p> <br/> The obtained result indicates that you need 8.17 g of sugar to prepare 100 g of solution: <br/> <br/> <p class="spip" style="text-align: center;"><img src='https://ejercicios-fyq.com/local/cache-TeX/e25d3d805fa0d6cf5030bbc04c5e644e.png' style="vertical-align:middle;" width="297" height="52" alt="500\ \cancel{g\ D}\cdot \frac{8.17\ g\ S}{100\ \cancel{g\ D}} = \fbox{\color[RGB]{192,0,0}{\bf 40.9\ g\ S}}" title="500\ \cancel{g\ D}\cdot \frac{8.17\ g\ S}{100\ \cancel{g\ D}} = \fbox{\color[RGB]{192,0,0}{\bf 40.9\ g\ S}}" /></p> </math></p></div>