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		<title>Relationship between molarity and normality (8380)</title>
		<link>https://ejercicios-fyq.com/Relationship-between-molarity-and-normality-8380</link>
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		<dc:date>2025-01-27T04:52:56Z</dc:date>
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		<dc:subject>Molarity</dc:subject>
		<dc:subject>SOLVED</dc:subject>
		<dc:subject>Normality</dc:subject>

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&lt;p&gt;Calculate the normality of the following solutions: a) (2 M) b) (0.4 M) c) (3 M) d) (1 M) e) (2 M)&lt;/p&gt;


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 <content:encoded>&lt;div class='rss_texte'&gt;&lt;p&gt;Calculate the normality of the following solutions: a) &lt;img src='https://ejercicios-fyq.com/local/cache-vignettes/L54xH20/2da7a629b8ae0d3a94f18434955efb1c-35b24.png?1733007720' style='vertical-align:middle;' width='54' height='20' alt=&#034;\ce{NOH2}&#034; title=&#034;\ce{NOH2}&#034; /&gt; (2 M) b) &lt;img src='https://ejercicios-fyq.com/local/cache-vignettes/L36xH13/f6fa3f3b19665b50c5e024ec7c43d21c-4bb6a.png?1733037371' style='vertical-align:middle;' width='36' height='13' alt=&#034;\ce{KOH}&#034; title=&#034;\ce{KOH}&#034; /&gt; (0.4 M) c) &lt;img src='https://ejercicios-fyq.com/local/cache-vignettes/L59xH21/99b33dcab22a7317297ec36909d9f4b5-1645e.png?1734460664' style='vertical-align:middle;' width='59' height='21' alt=&#034;\ce{H2SO_3}&#034; title=&#034;\ce{H2SO_3}&#034; /&gt; (3 M) d) &lt;img src='https://ejercicios-fyq.com/local/cache-vignettes/L60xH18/cb337c813d41bf56e06ee934b6dd5172-2fb87.png?1733018315' style='vertical-align:middle;' width='60' height='18' alt=&#034;\ce{Al(OH)3}&#034; title=&#034;\ce{Al(OH)3}&#034; /&gt; (1 M) e) &lt;img src='https://ejercicios-fyq.com/local/cache-vignettes/L44xH15/c1d8eeacb2c44237bbc847837c11be56-d66f1.png?1732958435' style='vertical-align:middle;' width='44' height='15' alt=&#034;\ce{NaCl}&#034; title=&#034;\ce{NaCl}&#034; /&gt; (2 M)&lt;/math&gt;&lt;/p&gt;&lt;/div&gt;
		&lt;hr /&gt;
		&lt;div &lt;div class='rss_ps'&gt;&lt;p&gt;Normality is defined as the number of equivalents of solute in one liter of solution. The mass of an equivalent is the molecular mass divided by the number of &#034;H&#034; or &#034;OH&#034; groups in the acid or base considered. This means that the relationship between normality and molarity is that normality is equal to molarity multiplied by the number of &#034;H&#034; or &#034;OH&#034; groups in the species. &lt;br/&gt; &lt;br/&gt; a) &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/0738344972da2610cbfb98b6572fd9ed.png' style=&#034;vertical-align:middle;&#034; width=&#034;219&#034; height=&#034;28&#034; alt=&#034;\ce{NOH2}\ (2\ M)\ \to\ \fbox{\color[RGB]{192,0,0}{\bf 4\ N}}&#034; title=&#034;\ce{NOH2}\ (2\ M)\ \to\ \fbox{\color[RGB]{192,0,0}{\bf 4\ N}}&#034; /&gt; &lt;br/&gt; &lt;br/&gt; b) &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/231c6ba56c3a66f0d5cb08147fac806e.png' style=&#034;vertical-align:middle;&#034; width=&#034;246&#034; height=&#034;28&#034; alt=&#034;\ce{KOH}\ (0.4\ M)\ \to\ \fbox{\color[RGB]{192,0,0}{\bf 0.4\ N}}&#034; title=&#034;\ce{KOH}\ (0.4\ M)\ \to\ \fbox{\color[RGB]{192,0,0}{\bf 0.4\ N}}&#034; /&gt; &lt;br/&gt; &lt;br/&gt; c) &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/316e09d835185628eb3f2872f7045160.png' style=&#034;vertical-align:middle;&#034; width=&#034;224&#034; height=&#034;28&#034; alt=&#034;\ce{H_2SO_3}\ (3\ M)\ \to\ \fbox{\color[RGB]{192,0,0}{\bf 6\ N}}&#034; title=&#034;\ce{H_2SO_3}\ (3\ M)\ \to\ \fbox{\color[RGB]{192,0,0}{\bf 6\ N}}&#034; /&gt; &lt;br/&gt; &lt;br/&gt; d) &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/b2dbaf95dd7ea26cea3bf959928e2faa.png' style=&#034;vertical-align:middle;&#034; width=&#034;243&#034; height=&#034;28&#034; alt=&#034;\ce{Al(OH)_3}\ (1\ M)\ \to\ \fbox{\color[RGB]{192,0,0}{\bf 3\ N}}&#034; title=&#034;\ce{Al(OH)_3}\ (1\ M)\ \to\ \fbox{\color[RGB]{192,0,0}{\bf 3\ N}}&#034; /&gt; &lt;br/&gt; &lt;br/&gt; e) &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/c83eb18dd999260e0f60514be891e947.png' style=&#034;vertical-align:middle;&#034; width=&#034;210&#034; height=&#034;28&#034; alt=&#034;\ce{NaCl}\ (2\ M)\ \to\ \fbox{\color[RGB]{192,0,0}{\bf 2\ N}}&#034; title=&#034;\ce{NaCl}\ (2\ M)\ \to\ \fbox{\color[RGB]{192,0,0}{\bf 2\ N}}&#034; /&gt; (because it is a salt with a 1:1 stoichiometry between its ions).&lt;/math&gt;&lt;/p&gt;&lt;/div&gt;
		
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