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	<title>EjerciciosFyQ</title>
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	<description>Ejercicios Resueltos, Situaciones de aprendizaje y V&#205;DEOS de F&#237;sica y Qu&#237;mica para Secundaria y Bachillerato</description>
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<item xml:lang="es">
		<title>General gas law (8316)</title>
		<link>https://ejercicios-fyq.com/General-gas-law-8316</link>
		<guid isPermaLink="true">https://ejercicios-fyq.com/General-gas-law-8316</guid>
		<dc:date>2024-09-17T02:52:07Z</dc:date>
		<dc:format>text/html</dc:format>
		<dc:language>es</dc:language>
		<dc:creator>F_y_Q</dc:creator>


		<dc:subject>State equation</dc:subject>
		<dc:subject>Gas laws</dc:subject>
		<dc:subject>SOLVED</dc:subject>

		<description>
&lt;p&gt;Calculate the final temperature of a gas enclosed in a volume of 2 L at 1 atm, if we reduce its volume to 0.5 L and its pressure increases to 3.8 atm.&lt;/p&gt;


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&lt;a href="https://ejercicios-fyq.com/SOLVED" rel="tag"&gt;SOLVED&lt;/a&gt;

		</description>


 <content:encoded>&lt;div class='rss_texte'&gt;&lt;p&gt;Calculate the final temperature of a gas enclosed in a volume of 2 L at 1 atm, if we reduce its volume to 0.5 L and its pressure increases to 3.8 atm.&lt;/p&gt;&lt;/div&gt;
		&lt;hr /&gt;
		&lt;div &lt;div class='rss_ps'&gt;&lt;p&gt;You will use the state equation of gases: &lt;br/&gt; &lt;br/&gt; &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/ffed963df0c5c03aa73305d0c53d9676.png' style=&#034;vertical-align:middle;&#034; width=&#034;171&#034; height=&#034;51&#034; alt=&#034;\color[RGB]{2,112,20}{\bm{\frac{P_1\cdot V_1}{T_1} = \frac{P_2\cdot V_2}{T_2}}}}&#034; title=&#034;\color[RGB]{2,112,20}{\bm{\frac{P_1\cdot V_1}{T_1} = \frac{P_2\cdot V_2}{T_2}}}}&#034; /&gt; &lt;br/&gt; &lt;br/&gt; Solving for the value of &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/6a058d102910f33a7d4cf9ea23067b8c.png' style=&#034;vertical-align:middle;&#034; width=&#034;23&#034; height=&#034;40&#034; alt=&#034;T_2&#034; title=&#034;T_2&#034; /&gt;: &lt;br/&gt; &lt;br/&gt; &lt;p class=&#034;spip&#034; style=&#034;text-align: center;&#034;&gt;&lt;img src='https://ejercicios-fyq.com/local/cache-TeX/fc4c300791b1c9df86ae6ffb2261b125.png' style=&#034;vertical-align:middle;&#034; width=&#034;514&#034; height=&#034;50&#034; alt=&#034;T_2 = \frac{P_2\cdot V_2\cdot T_1}{P_1\cdot V_1} = \frac{3.8\ \cancel{atm}\cdot 0.5\ \cancel{L}\cdot 298\ K}{1\ \cancel{atm}\cdot 2\ \cancel{L}} = \fbox{\color[RGB]{192,0,0}{\bf 283.1\ K}}&#034; title=&#034;T_2 = \frac{P_2\cdot V_2\cdot T_1}{P_1\cdot V_1} = \frac{3.8\ \cancel{atm}\cdot 0.5\ \cancel{L}\cdot 298\ K}{1\ \cancel{atm}\cdot 2\ \cancel{L}} = \fbox{\color[RGB]{192,0,0}{\bf 283.1\ K}}&#034; /&gt;&lt;/p&gt;
&lt;/math&gt;&lt;/p&gt;&lt;/div&gt;
		
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	</item>
<item xml:lang="es">
		<title>Application of Graham's law: hydrogen diffusion rate (8308)</title>
		<link>https://ejercicios-fyq.com/Application-of-Graham-s-law-hydrogen-diffusion-rate-8308</link>
		<guid isPermaLink="true">https://ejercicios-fyq.com/Application-of-Graham-s-law-hydrogen-diffusion-rate-8308</guid>
		<dc:date>2024-09-12T04:06:10Z</dc:date>
		<dc:format>text/html</dc:format>
		<dc:language>es</dc:language>
		<dc:creator>F_y_Q</dc:creator>


		<dc:subject>Gas laws</dc:subject>
		<dc:subject>Graham's law</dc:subject>
		<dc:subject>SOLVED</dc:subject>

		<description>
&lt;p&gt;Determine the diffusion rate of hydrogen, knowing that the diffusion rate of oxygen is 2 minutes.&lt;/p&gt;


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&lt;a href="https://ejercicios-fyq.com/Matter-and-gas-laws" rel="directory"&gt;Matter and gas laws&lt;/a&gt;

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&lt;a href="https://ejercicios-fyq.com/SOLVED" rel="tag"&gt;SOLVED&lt;/a&gt;

		</description>


 <content:encoded>&lt;div class='rss_texte'&gt;&lt;p&gt;Determine the diffusion rate of hydrogen, knowing that the diffusion rate of oxygen is 2 minutes.&lt;/p&gt;&lt;/div&gt;
		&lt;hr /&gt;
		&lt;div &lt;div class='rss_ps'&gt;&lt;p&gt;Graham's law relates the diffusion rates of two gases to their molecular masses. If the gases are A and B, the relationship is: &lt;br/&gt; &lt;br/&gt; &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/4cf3fe04d22fc72e2d726e95ac2bdc33.png' style=&#034;vertical-align:middle;&#034; width=&#034;126&#034; height=&#034;65&#034; alt=&#034;\color[RGB]{2,112,20}{\bm{\frac{v_A}{v_B} = \sqrt{\frac{M_B}{M_A}}}}&#034; title=&#034;\color[RGB]{2,112,20}{\bm{\frac{v_A}{v_B} = \sqrt{\frac{M_B}{M_A}}}}&#034; /&gt; &lt;br/&gt; &lt;br/&gt; For hydrogen and oxygen, both being diatomic, the molecular masses are: &lt;br/&gt; &lt;br/&gt; &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/fa228ad48fcef891303029aae15bb4aa.png' style=&#034;vertical-align:middle;&#034; width=&#034;179&#034; height=&#034;52&#034; alt=&#034;\left \ce{H2}: 2\cdot 1 = {\color[RGB]{0,112,192}{\bf 2\ u}} \atop \ce{O2}: 2\cdot 16 = {\color[RGB]{0,112,192}{\bf 32\ u}} \right \}&#034; title=&#034;\left \ce{H2}: 2\cdot 1 = {\color[RGB]{0,112,192}{\bf 2\ u}} \atop \ce{O2}: 2\cdot 16 = {\color[RGB]{0,112,192}{\bf 32\ u}} \right \}&#034; /&gt; &lt;br/&gt; &lt;br/&gt; The relationship between their diffusion rates will be: &lt;br/&gt; &lt;br/&gt; &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/d7383bc419efafca3c82287879aa12d2.png' style=&#034;vertical-align:middle;&#034; width=&#034;236&#034; height=&#034;55&#034; alt=&#034;\frac{v_{\ce{H_2}}}{v_{\ce{O_2}}}= \sqrt{\frac{32\ \cancel{u}}{2\ \cancel{u}}} = \sqrt{16} = \color[RGB]{0,112,192}{\bf 4}&#034; title=&#034;\frac{v_{\ce{H_2}}}{v_{\ce{O_2}}}= \sqrt{\frac{32\ \cancel{u}}{2\ \cancel{u}}} = \sqrt{16} = \color[RGB]{0,112,192}{\bf 4}&#034; /&gt; &lt;br/&gt; &lt;br/&gt; This means hydrogen diffuses four times faster than oxygen, so &lt;b&gt;the diffusion rate of hydrogen will be 0.5 minutes&lt;/b&gt;, or 30 seconds&lt;/b&gt;.&lt;/math&gt;&lt;/p&gt;&lt;/div&gt;
		
		</content:encoded>


		

	</item>
<item xml:lang="es">
		<title>Is ethyl alcohol a mixture or a pure substance? (8287)</title>
		<link>https://ejercicios-fyq.com/Is-ethyl-alcohol-a-mixture-or-a-pure-substance-8287</link>
		<guid isPermaLink="true">https://ejercicios-fyq.com/Is-ethyl-alcohol-a-mixture-or-a-pure-substance-8287</guid>
		<dc:date>2024-08-13T03:54:10Z</dc:date>
		<dc:format>text/html</dc:format>
		<dc:language>es</dc:language>
		<dc:creator>F_y_Q</dc:creator>


		<dc:subject>Mixtures</dc:subject>
		<dc:subject>Pure substances</dc:subject>
		<dc:subject>SOLVED</dc:subject>

		<description>
&lt;p&gt;Is ethyl alcohol an element, a compound, or a mixture?&lt;/p&gt;


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&lt;a href="https://ejercicios-fyq.com/SOLVED" rel="tag"&gt;SOLVED&lt;/a&gt;

		</description>


 <content:encoded>&lt;div class='rss_texte'&gt;&lt;p&gt;Is ethyl alcohol an element, a compound, or a mixture?&lt;/p&gt;&lt;/div&gt;
		&lt;hr /&gt;
		&lt;div &lt;div class='rss_ps'&gt;&lt;p&gt;Ethyl alcohol, or ethanol, falls under what we call &#034;pure substances&#034;, so you should discard the idea that it is a mixture (except in the case mentioned at the end). &lt;br/&gt; &lt;br/&gt; Within pure substances, you can find elements, which are made up of a single type of atom, and compounds, which are made up of more than one type of atom. &lt;br/&gt; &lt;br/&gt; Ethyl alcohol &lt;b&gt;is a compound&lt;/b&gt; (&lt;img src='https://ejercicios-fyq.com/local/cache-TeX/80b2667acc2236dd31dbdc458188bdb7.png' style=&#034;vertical-align:middle;&#034; width=&#034;128&#034; height=&#034;20&#034; alt=&#034;\color[RGB]{0,112,192}{\textbf{\ce{CH3CH2OH}}}&#034; title=&#034;\color[RGB]{0,112,192}{\textbf{\ce{CH3CH2OH}}}&#034; /&gt;). As you can see, it contains carbon, hydrogen, and oxygen atoms. &lt;br/&gt; &lt;br/&gt; However, if we refer to the alcohol that can be purchased in stores or pharmacies, we would be talking about a mixture because it is not pure alcohol; it contains water. This is why the label indicates that it is &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/19a328a26c3e064c2db5a7f0df194d22.png' style=&#034;vertical-align:middle;&#034; width=&#034;41&#034; height=&#034;19&#034; alt=&#034;96\ \%&#034; title=&#034;96\ \%&#034; /&gt; or &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/be843b9a3aab9685c02afcec6c3cff29.png' style=&#034;vertical-align:middle;&#034; width=&#034;31&#034; height=&#034;14&#034; alt=&#034;70\ \%&#034; title=&#034;70\ \%&#034; /&gt;, for example.&lt;/math&gt;&lt;/p&gt;&lt;/div&gt;
		
		</content:encoded>


		

	</item>
<item xml:lang="es">
		<title>Calculation of the density of a sphere knowing its diameter (8285)</title>
		<link>https://ejercicios-fyq.com/Calculation-of-the-density-of-a-sphere-knowing-its-diameter-8285</link>
		<guid isPermaLink="true">https://ejercicios-fyq.com/Calculation-of-the-density-of-a-sphere-knowing-its-diameter-8285</guid>
		<dc:date>2024-08-12T14:03:58Z</dc:date>
		<dc:format>text/html</dc:format>
		<dc:language>es</dc:language>
		<dc:creator>F_y_Q</dc:creator>


		<dc:subject>Density</dc:subject>
		<dc:subject>SOLVED</dc:subject>

		<description>
&lt;p&gt;Determine the density of a sphere with a diameter of 6 cm, given that its mass is 250 g.&lt;/p&gt;


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&lt;a href="https://ejercicios-fyq.com/SOLVED" rel="tag"&gt;SOLVED&lt;/a&gt;

		</description>


 <content:encoded>&lt;div class='rss_texte'&gt;&lt;p&gt;Determine the density of a sphere with a diameter of 6 cm, given that its mass is 250 g.&lt;/p&gt;&lt;/div&gt;
		&lt;hr /&gt;
		&lt;div &lt;div class='rss_ps'&gt;&lt;p&gt;To calculate the density of a system, you need to know its mass and volume. First, you must calculate the volume of the sphere using the volume equation: &lt;br/&gt; &lt;br/&gt; &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/1f85f9712dae0faef492eb13de8daf92.png' style=&#034;vertical-align:middle;&#034; width=&#034;125&#034; height=&#034;48&#034; alt=&#034;\color[RGB]{2,112,20}{\bm{V = \frac{4}{3}\pi \cdot R^3}}&#034; title=&#034;\color[RGB]{2,112,20}{\bm{V = \frac{4}{3}\pi \cdot R^3}}&#034; /&gt; &lt;br/&gt; &lt;br/&gt; Given that the diameter is provided, which is twice the radius, the radius of the sphere is 3 cm. Substitute and calculate: &lt;br/&gt; &lt;br/&gt; &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/cdcf158db264a50332bd8866bd76e5d0.png' style=&#034;vertical-align:middle;&#034; width=&#034;263&#034; height=&#034;45&#034; alt=&#034;V = \frac{4}{3}\pi \cdot 3^3\ cm^3 = \color[RGB]{0,112,192}{\bm{113\ cm^3}}&#034; title=&#034;V = \frac{4}{3}\pi \cdot 3^3\ cm^3 = \color[RGB]{0,112,192}{\bm{113\ cm^3}}&#034; /&gt; &lt;br/&gt; &lt;br/&gt; Now you can calculate the density of the sphere by dividing the mass by the volume: &lt;br/&gt; &lt;br/&gt; &lt;p class=&#034;spip&#034; style=&#034;text-align: center;&#034;&gt;&lt;img src='https://ejercicios-fyq.com/local/cache-TeX/2105503a2901cbe3e5724f89debe809a.png' style=&#034;vertical-align:middle;&#034; width=&#034;299&#034; height=&#034;45&#034; alt=&#034;\rho = \frac{m}{V} = \frac{250\ g}{113\ cm^3} = \fbox{\color[RGB]{192,0,0}{\bm{2.21\ \frac{g}{cm^3}}}}&#034; title=&#034;\rho = \frac{m}{V} = \frac{250\ g}{113\ cm^3} = \fbox{\color[RGB]{192,0,0}{\bm{2.21\ \frac{g}{cm^3}}}}&#034; /&gt;&lt;/p&gt;
&lt;/math&gt;&lt;/p&gt;&lt;/div&gt;
		
		</content:encoded>


		

	</item>
<item xml:lang="es">
		<title>Density of a sample of solid (4502)</title>
		<link>https://ejercicios-fyq.com/Density-of-a-sample-of-solid-4502</link>
		<guid isPermaLink="true">https://ejercicios-fyq.com/Density-of-a-sample-of-solid-4502</guid>
		<dc:date>2018-04-18T05:49:51Z</dc:date>
		<dc:format>text/html</dc:format>
		<dc:language>es</dc:language>
		<dc:creator>F_y_Q</dc:creator>


		<dc:subject>Densidad</dc:subject>
		<dc:subject>RESUELTO</dc:subject>
		<dc:subject>Biling&#252;ismo</dc:subject>
		<dc:subject>SOLVED</dc:subject>

		<description>
&lt;p&gt;A 15 mL sample of a solid is weighed, and the recorded mass is 29 g. What is the density of the solid?&lt;/p&gt;


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&lt;a href="https://ejercicios-fyq.com/Bilinguismo" rel="tag"&gt;Biling&#252;ismo&lt;/a&gt;, 
&lt;a href="https://ejercicios-fyq.com/SOLVED" rel="tag"&gt;SOLVED&lt;/a&gt;

		</description>


 <content:encoded>&lt;div class='rss_texte'&gt;&lt;p&gt;A 15 mL sample of a solid is weighed, and the recorded mass is 29 g. What is the density of the solid?&lt;/p&gt;&lt;/div&gt;
		&lt;hr /&gt;
		&lt;div &lt;div class='rss_ps'&gt;&lt;p&gt;You only have to use the density equation: &lt;br/&gt; &lt;br/&gt; &lt;p class=&#034;spip&#034; style=&#034;text-align: center;&#034;&gt;&lt;img src='https://ejercicios-fyq.com/local/cache-TeX/98f8e7e120a4a3fb3fa8c075931ece00.png' style=&#034;vertical-align:middle;&#034; width=&#034;405&#034; height=&#034;47&#034; alt=&#034;{\color[RGB]{2,112,20}{\bm{d =\frac{m}{V}}}}\ \to\ d = \frac{29\ g}{15\ mL} = \fbox{\color[RGB]{192,0,0}{\bm{1.93\ g\cdot mL^{-1}}}}&#034; title=&#034;{\color[RGB]{2,112,20}{\bm{d =\frac{m}{V}}}}\ \to\ d = \frac{29\ g}{15\ mL} = \fbox{\color[RGB]{192,0,0}{\bm{1.93\ g\cdot mL^{-1}}}}&#034; /&gt;&lt;/p&gt;
&lt;/math&gt;&lt;/p&gt;&lt;/div&gt;
		
		</content:encoded>


		

	</item>
<item xml:lang="es">
		<title>Density of a substance (3661)</title>
		<link>https://ejercicios-fyq.com/Density-of-a-substance-3661</link>
		<guid isPermaLink="true">https://ejercicios-fyq.com/Density-of-a-substance-3661</guid>
		<dc:date>2016-08-08T18:21:41Z</dc:date>
		<dc:format>text/html</dc:format>
		<dc:language>es</dc:language>
		<dc:creator>F_y_Q</dc:creator>


		<dc:subject>Density</dc:subject>
		<dc:subject>SOLVED</dc:subject>

		<description>
&lt;p&gt;The volume of 200 g of a substance is 10 L. What is its density?&lt;/p&gt;


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&lt;a href="https://ejercicios-fyq.com/SOLVED" rel="tag"&gt;SOLVED&lt;/a&gt;

		</description>


 <content:encoded>&lt;div class='rss_texte'&gt;&lt;p&gt;The volume of 200 g of a substance is 10 L. What is its density?&lt;/p&gt;&lt;/div&gt;
		&lt;hr /&gt;
		&lt;div &lt;div class='rss_ps'&gt;&lt;p&gt;Density is defined by: &lt;br/&gt; &lt;br/&gt; &lt;p class=&#034;spip&#034; style=&#034;text-align: center;&#034;&gt;&lt;img src='https://ejercicios-fyq.com/local/cache-TeX/2dbfe0965193bde3fc64287025abf2ae.png' style=&#034;vertical-align:middle;&#034; width=&#034;295&#034; height=&#034;47&#034; alt=&#034;{\color[RGB]{2,112,20}{\bm{\rho = \frac{m}{V}}}} = \frac{200\ g}{10\ L} = \fbox{\color[RGB]{192,0,0}{\bm{20\ g\cdot L^{-1}}}}&#034; title=&#034;{\color[RGB]{2,112,20}{\bm{\rho = \frac{m}{V}}}} = \frac{200\ g}{10\ L} = \fbox{\color[RGB]{192,0,0}{\bm{20\ g\cdot L^{-1}}}}&#034; /&gt;&lt;/p&gt;
&lt;/math&gt;&lt;/p&gt;&lt;/div&gt;
		
		</content:encoded>


		

	</item>
<item xml:lang="es">
		<title>Knowledge review: True or false questions (3114)</title>
		<link>https://ejercicios-fyq.com/Knowledge-review-True-or-false-questions-3114</link>
		<guid isPermaLink="true">https://ejercicios-fyq.com/Knowledge-review-True-or-false-questions-3114</guid>
		<dc:date>2015-04-25T03:59:05Z</dc:date>
		<dc:format>text/html</dc:format>
		<dc:language>es</dc:language>
		<dc:creator>F_y_Q</dc:creator>


		<dc:subject>Electric force</dc:subject>
		<dc:subject>Density</dc:subject>
		<dc:subject>Mixtures</dc:subject>
		<dc:subject>Separation methods</dc:subject>
		<dc:subject>SOLVED</dc:subject>

		<description>
&lt;p&gt;Decide if these sentences are true or false and rewrite the false sentences correctly. Be careful because each mistake discounts a right answer: &lt;br class='autobr' /&gt;
a) The density of a solution is equal to the mass of the solute divided by the volume of the solvent. &lt;br class='autobr' /&gt;
b) The interaction between unlike charges is a repulsion force. &lt;br class='autobr' /&gt;
c) Distillation is the method to separate miscible liquids. &lt;br class='autobr' /&gt;
d) Decantation is the correct method to separate a mix of alcohol and water.&lt;/p&gt;


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&lt;a href="https://ejercicios-fyq.com/Mixtures" rel="tag"&gt;Mixtures&lt;/a&gt;, 
&lt;a href="https://ejercicios-fyq.com/Separation-methods" rel="tag"&gt;Separation methods&lt;/a&gt;, 
&lt;a href="https://ejercicios-fyq.com/SOLVED" rel="tag"&gt;SOLVED&lt;/a&gt;

		</description>


 <content:encoded>&lt;div class='rss_texte'&gt;&lt;p&gt;Decide if these sentences are true or false and rewrite the false sentences correctly. Be careful because each mistake discounts a right answer:&lt;/p&gt;
&lt;p&gt;a) The density of a solution is equal to the mass of the solute divided by the volume of the solvent.&lt;/p&gt;
&lt;p&gt;b) The interaction between unlike charges is a repulsion force.&lt;/p&gt;
&lt;p&gt;c) Distillation is the method to separate miscible liquids.&lt;/p&gt;
&lt;p&gt;d) Decantation is the correct method to separate a mix of alcohol and water.&lt;/p&gt;&lt;/div&gt;
		&lt;hr /&gt;
		&lt;div &lt;div class='rss_ps'&gt;&lt;p&gt;a) &lt;b&gt;FALSE&lt;/b&gt;. The density of a solution is equal to the mass of the &lt;b&gt;solution&lt;/b&gt; divided by the volume of &lt;b&gt;solution&lt;/b&gt;.&lt;/p&gt;
&lt;p&gt;b) &lt;b&gt;FALSE&lt;/b&gt;. The interaction between unlike charges is an &lt;b&gt;attraction&lt;/b&gt; force.&lt;/p&gt;
&lt;p&gt;c) &lt;b&gt;TRUE&lt;/b&gt;.&lt;/p&gt;
&lt;p&gt;d) &lt;b&gt;FALSE&lt;/b&gt;. &lt;b&gt;Distillation&lt;/b&gt; is the correct method to separate a mix of alcohol and water.&lt;/p&gt;&lt;/div&gt;
		
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<item xml:lang="es">
		<title>General gas law: final volume of a gas (1927)</title>
		<link>https://ejercicios-fyq.com/General-gas-law-final-volume-of-a-gas-1927</link>
		<guid isPermaLink="true">https://ejercicios-fyq.com/General-gas-law-final-volume-of-a-gas-1927</guid>
		<dc:date>2012-11-05T07:22:34Z</dc:date>
		<dc:format>text/html</dc:format>
		<dc:language>es</dc:language>
		<dc:creator>F_y_Q</dc:creator>


		<dc:subject>EDICO</dc:subject>
		<dc:subject>State equation</dc:subject>
		<dc:subject>General gas law</dc:subject>
		<dc:subject>Gas laws</dc:subject>
		<dc:subject>SOLVED</dc:subject>

		<description>
&lt;p&gt;Calculate the final volume of a gas at and 1.1 atm, when its volume is 3 L and the temperature and pressure are increased to and 1.3 atm.&lt;/p&gt;


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 <content:encoded>&lt;div class='rss_texte'&gt;&lt;p&gt;Calculate the final volume of a gas at &lt;img src='https://ejercicios-fyq.com/local/cache-vignettes/L55xH42/e377e6d6fa467c168c039e4ec52eff00-8b3d5.png?1732957639' style='vertical-align:middle;' width='55' height='42' alt=&#034;30\ ^oC&#034; title=&#034;30\ ^oC&#034; /&gt; and 1.1 atm, when its volume is 3 L and the temperature and pressure are increased to &lt;img src='https://ejercicios-fyq.com/local/cache-vignettes/L52xH17/63a42815bec477dc118cf61ee35689fc-6eeae.png?1732957639' style='vertical-align:middle;' width='52' height='17' alt=&#034;42\ ^oC&#034; title=&#034;42\ ^oC&#034; /&gt; and 1.3 atm.&lt;/math&gt;&lt;/p&gt;&lt;/div&gt;
		&lt;hr /&gt;
		&lt;div &lt;div class='rss_ps'&gt;&lt;p&gt;First, isolate the final volume in the general gas equation: &lt;br/&gt; &lt;br/&gt; &lt;img src='https://ejercicios-fyq.com/local/cache-TeX/0e536212229ed24e2f72242063e33f3f.png' style=&#034;vertical-align:middle;&#034; width=&#034;366&#034; height=&#034;51&#034; alt=&#034;\frac{P_1\cdot V_1}{T_1} = \frac{P_2\cdot V_2}{T_2}\ \to\ \color[RGB]{2,112,20}{\bm{V_2= \frac{P_1\cdot V_1\cdot T_2}{P_2\cdot T_1}}}&#034; title=&#034;\frac{P_1\cdot V_1}{T_1} = \frac{P_2\cdot V_2}{T_2}\ \to\ \color[RGB]{2,112,20}{\bm{V_2= \frac{P_1\cdot V_1\cdot T_2}{P_2\cdot T_1}}}&#034; /&gt; &lt;br/&gt; &lt;br/&gt; Replace the given data in the equation. Remember that the temperature must be expressed on the Kelvin scale: &lt;p class=&#034;spip&#034; style=&#034;text-align: center;&#034;&gt;&lt;img src='https://ejercicios-fyq.com/local/cache-TeX/6a568b6f1f7c57047becd5d7b56e31af.png' style=&#034;vertical-align:middle;&#034; width=&#034;352&#034; height=&#034;48&#034; alt=&#034;V_2= \frac{1.1\ \cancel{atm}\cdot 3\ L\cdot 315\ \cancel{K}}{1.3\ \cancel{atm}\cdot 303\ \cancel{K}} = \fbox{\color[RGB]{192,0,0}{\bf 2.64\ L}}&#034; title=&#034;V_2= \frac{1.1\ \cancel{atm}\cdot 3\ L\cdot 315\ \cancel{K}}{1.3\ \cancel{atm}\cdot 303\ \cancel{K}} = \fbox{\color[RGB]{192,0,0}{\bf 2.64\ L}}&#034; /&gt;&lt;/p&gt;
&lt;/math&gt;&lt;/p&gt;
&lt;p&gt; &lt;br/&gt;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;&lt;a href=&#034;https://ejercicios-fyq.com/Situaciones-de-aprendizaje/EDICO/Ej_1927.edi&#034; download&gt;Download the problem statement and solution in EDICO format if needed.&lt;/a&gt;&lt;/b&gt;&lt;/p&gt;&lt;/div&gt;
		
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	</item>
<item xml:lang="es">
		<title>Defining pressure, heat and the Molecular Kinetic Theory for gases</title>
		<link>https://ejercicios-fyq.com/Defining-pressure-heat-and-the-Molecular-Kinetic-Theory-for-gases</link>
		<guid isPermaLink="true">https://ejercicios-fyq.com/Defining-pressure-heat-and-the-Molecular-Kinetic-Theory-for-gases</guid>
		<dc:date>2012-11-05T07:22:32Z</dc:date>
		<dc:format>text/html</dc:format>
		<dc:language>es</dc:language>
		<dc:creator>F_y_Q</dc:creator>


		<dc:subject>Heat</dc:subject>
		<dc:subject>Molecular kinetic theory</dc:subject>
		<dc:subject>SOLVED</dc:subject>

		<description>
&lt;p&gt;Define, with your own words, the following concepts: &lt;br class='autobr' /&gt;
a) Pressure &lt;br class='autobr' /&gt;
b) Heat &lt;br class='autobr' /&gt;
c) Molecular Kinetic Theory for gases.&lt;/p&gt;


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&lt;a href="https://ejercicios-fyq.com/SOLVED" rel="tag"&gt;SOLVED&lt;/a&gt;

		</description>


 <content:encoded>&lt;div class='rss_texte'&gt;&lt;p&gt;Define, with your own words, the following concepts:&lt;/p&gt;
&lt;p&gt;a) Pressure&lt;/p&gt;
&lt;p&gt;b) Heat&lt;/p&gt;
&lt;p&gt;c) Molecular Kinetic Theory for gases.&lt;/p&gt;&lt;/div&gt;
		&lt;hr /&gt;
		&lt;div &lt;div class='rss_ps'&gt;&lt;p&gt;a) &lt;u&gt;Pressure&lt;/u&gt;: It is the number of collisions of the particles of a system enclosed in a container, per unit area. It is measured in pascals (Pa) in the International System of Units (SI).&lt;/p&gt;
&lt;p&gt;b) &lt;u&gt;Heat&lt;/u&gt;: Heat is a form of energy that is transferred between systems or objects with different temperatures. It flows from the hotter object to the cooler one until thermal equilibrium is reached.&lt;/p&gt;
&lt;p&gt;c) &lt;u&gt;Molecular Kinetic Theory for gases&lt;/u&gt;: The Molecular Kinetic Theory for gases explains the behavior of gases in terms of the motion of their particles. It states that gas pressure is due to the collisions of molecules with the walls of the container, and the temperature of the gas is proportional to the average kinetic energy of the molecules.&lt;/p&gt;&lt;/div&gt;
		
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