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General gas law (8316)
Martes 17 de septiembre de 2024, por
Calculate the final temperature of a gas enclosed in a volume of 2 L at 1 atm, if we reduce its volume to 0.5 L and its pressure increases to 3.8 atm.
You will use the state equation of gases:
![\color[RGB]{2,112,20}{\bm{\frac{P_1\cdot V_1}{T_1} = \frac{P_2\cdot V_2}{T_2}}}}](local/cache-vignettes/L171xH51/ffed963df0c5c03aa73305d0c53d9676-bdb4d.png?1732996360 "\color[RGB]{2,112,20}{\bm{\frac{P_1\cdot V_1}{T_1} = \frac{P_2\cdot V_2}{T_2}}}}")
Solving for the value of 
:
![T_2 = \frac{P_2\cdot V_2\cdot T_1}{P_1\cdot V_1} = \frac{3.8\ \cancel{atm}\cdot 0.5\ \cancel{L}\cdot 298\ K}{1\ \cancel{atm}\cdot 2\ \cancel{L}} = \fbox{\color[RGB]{192,0,0}{\bf 283.1\ K}}](local/cache-vignettes/L514xH50/fc4c300791b1c9df86ae6ffb2261b125-f2dad.png?1732996360 "T_2 = \frac{P_2\cdot V_2\cdot T_1}{P_1\cdot V_1} = \frac{3.8\ \cancel{atm}\cdot 0.5\ \cancel{L}\cdot 298\ K}{1\ \cancel{atm}\cdot 2\ \cancel{L}} = \fbox{\color[RGB]{192,0,0}{\bf 283.1\ K}}")