Mass of iron in a heat transference 0001

, por F_y_Q

What mass of iron would need 1 450 cal of energy in order to raise its temperature by 19.7 ºC?


The specific heat of iron is 0,113 cal/g·ºC. Clearing the mass in the equation below:

Q = m\cdot c_e\cdot \Delta T\ \to\ m = \frac{Q}{c_e\cdot \Delta T} = \frac{1\ 450\ cal}{0,113\frac{cal}{g\cdot ^\circ C}\cdot 19,7^\circ C} = \bf 651,36\ g