Mass of iron in a heat transfer (3589)

, por F_y_Q

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What mass of iron would require 1 450 cal of energy to raise its temperature by 19.7\ ^oC?

The specific heat of iron is 0.113\ cal\cdot g^{-1}\cdot ^oC^{-1}

P.-S.

To find the mass, use the formula:

\color[RGB]{2,112,20}{\bm{Q= m\cdot c_e\cdot \Delta T}}

Rearrange the equation to solve for mass:

m = \frac{Q}{c_e\cdot \Delta T} = \frac{1\ 450\ \text{cal}}{0.113\ \frac{\cancel{cal}}{g\cdot \cancel{^oC}}\cdot 19.7\ \cancel{^oC}} = \fbox{\color[RGB]{192,0,0}{\bf 651.4\ g}}