Efficiency and useful power (8300)

, por F_y_Q

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A motor is supplied with a power of 1 000 W. If the efficiency of this motor is 80\ \%, calculate the useful power and the lost power.

P.-S.

Efficiency or performance is the ratio between the useful power and the supplied power:

\color[RGB]{2,112,20}{\bm{\rho = \frac{P_u}{P_T}\cdot 100}}

The useful power will be:

P_u = \frac{80}{100}\cdot P_T = 0.8\cdot 1\ 000\ W = \fbox{\color[RGB]{192,0,0}{\bf 800\ W}}


The lost power will be the difference between the supplied and the used power:

(1\ 000 - 800)\ W = \fbox{\color[RGB]{192,0,0}{\bf 200\ W}}

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