General gas law (8316)

, por F_y_Q

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Calculate the final temperature of a gas enclosed in a volume of 2 L at 1 atm, if we reduce its volume to 0.5 L and its pressure increases to 3.8 atm.

P.-S.

You will use the state equation of gases:

\color[RGB]{2,112,20}{\bm{\frac{P_1\cdot V_1}{T_1} = \frac{P_2\cdot V_2}{T_2}}}}

Solving for the value of T_2:

T_2 = \frac{P_2\cdot V_2\cdot T_1}{P_1\cdot V_1} = \frac{3.8\ \cancel{atm}\cdot 0.5\ \cancel{L}\cdot 298\ K}{1\ \cancel{atm}\cdot 2\ \cancel{L}} = \fbox{\color[RGB]{192,0,0}{\bf 283.1\ K}}